{"id":1391,"date":"2019-02-26T20:37:33","date_gmt":"2019-02-27T02:37:33","guid":{"rendered":"https:\/\/www.crpa-acrp-bulletin.ca\/?p=1391"},"modified":"2020-02-18T20:12:46","modified_gmt":"2020-02-19T02:12:46","slug":"crpar-prep-february-2019-preparation-a-la-designation-aacrp-fevrier-2019","status":"publish","type":"post","link":"https:\/\/www.crpa-acrp-bulletin.ca\/fr\/2019\/02\/26\/crpar-prep-february-2019-preparation-a-la-designation-aacrp-fevrier-2019\/","title":{"rendered":"CRPA(R) Prep, February 2019 \/ Pr\u00e9paration \u00e0 la d\u00e9signation (A)ACRP, f\u00e9vrier 2019"},"content":{"rendered":"

\"\"<\/p>\n

In this section of the Bulletin<\/em>, we introduce a question or two similar to the questions on the CRPA(R) exam. In the next issue, we will provide the solution. The intention is to give people an idea of the types of questions that we use on the CRPA(R) exam and perhaps convince more members to challenge the exam.<\/p>\n

If you already have your CRPA(R) designation, we invite you to\u00a0submit questions<\/a> to earn points for your registration maintenance!<\/p>\n

Question from the last issue:<\/h1>\n

So, let\u2019s take a look at the solution to the question from the last issue<\/a>.<\/p>\n

What is the transport index (TI) for a small package (less than 1 m2<\/sup>\u00a0cross-sectional area) being shipped as a \u201cCategory III \u2013 yellow\u201d with the following dose rates?<\/p>\n

Surface = 510 \u00b5Sv\/h
\n1 metre from surface = 43 \u00b5Sv\/h
\n10 metres from surface = 0.5 \u00b5Sv\/h<\/p>\n

Possible answers:
\na. 0.5
\nb. 4.3
\nc. 5.0
\nd. 8.6<\/p>\n

Proposed solution:<\/strong><\/p>\n

For anyone who sends any Class 7 shipments as part of their regular duties, or has had Class 7 TDG training, this question would be a freebie on a CRPA(R) exam! However, if you don\u2019t routinely ship nuclear substances or haven\u2019t heard the term \u201ctransport index\u201d before, this question is a little more difficult.<\/p>\n

If you plan to write the CRPA(R) exam and you don\u2019t routinely ship nuclear substances, you are going to have to study the Transportation of Dangerous Goods (TDG) Regulations<\/a> and the Packaging and Transport of Nuclear Substances Regulations (PTNSRs)<\/a>. The PTNSRs are provided at the exam, but the TDG Regulations and the International Atomic Energy Agency (IAEA) Transport Regulations (SSR-6)<\/a> are not provided. The PTNSRs heavily reference the other two regulations (among others).<\/p>\n

The following excerpt is from the Definitions section of the PTNSRs:<\/p>\n

transport index<\/strong><\/em>\u00a0has the same meaning as in the IAEA Regulations.<\/p>\n

Seeing as you will not have the IAEA Regulations with you in the exam, you need to study them in advance. Before I wrote my CRPA(R) exam, I took a TDG Class 7 refresher course. I killed two birds with one stone\u2014I did a little studying and got some work-appropriate training at the same time!<\/p>\n

When you do get around to studying, you will discover that, according to the IAEA regulations<\/a> (pages 62\u201363), the TI for a small package is determined by the following procedure:<\/p>\n

523 (a) Determine the maximum radiation level<\/em> in units of millisieverts per hour (mSv\/h) at a distance of 1 m from the external surfaces of the package, overpack, freight container or unpackaged LSA-I and SCO-I. The value determined shall be multiplied by 100 and the resulting number is the TI.<\/p>\n

. . .<\/p>\n

(c) The value obtained . . . shall be rounded up to the first decimal place (for example, 1.13 becomes 1.2), except that a value of 0.05 or less may be considered as zero.<\/p>\n

So, for this question, we were given three dose rates. We really only need the dose rate at 1 m of 43 \u00b5Sv\/h. (The other two dose rates have no bearing on the TI.) Then, the first step is to convert to mSv\/h.<\/p>\n

1000 \u00b5Sv\/h = 1 mSv\/h.<\/p>\n

Therefore: 43 \u00b5Sv\/h = 0.043 mSv\/h.<\/p>\n

Next, in accordance with the IAEA regulations, we multiply this number by 100. There is no unit for TI, but it is numerically identical to the dose rate at 1 m in mrem\/h.<\/p>\n

0.043 mSv\/h \u00d7 100 = 4.3<\/p>\n

The TI is 4.3 and the answer to our question is B.<\/p>\n

New question:<\/h1>\n

The amount of light emitted by a scintillation phosphor is proportional to what feature of photon energy?<\/p>\n

a. Absorbed
\nb. Attenuated
\nc. Scattered
\nd. Transmitted<\/p><\/div><\/div>\n

\n

Dans cette section du Bulletin<\/em>, nous proposons une ou deux questions similaires \u00e0 celles qui se trouvent dans un examen pour l\u2019agr\u00e9ment (A)ACRP, puis nous fournissons la solution dans le num\u00e9ro suivant. De cette fa\u00e7on, nous esp\u00e9rons donner aux gens une id\u00e9e du type de questions se trouvant dans l\u2019examen pour l\u2019agr\u00e9ment (A)ACRP et peut-\u00eatre ainsi convaincre plus de membres de passer l\u2019examen.<\/p>\n

Si vous avez d\u00e9j\u00e0 la d\u00e9signation (A)ACRP, nous vous invitons \u00e0 soumettre des questions<\/a> pour cette chronique, afin de gagner des points pour le maintien de votre agr\u00e9ment.<\/p>\n

Question du dernier num\u00e9ro\u00a0:<\/h1>\n

\u00c9tudions la solution \u00e0 la question du dernier num\u00e9ro<\/a>.<\/p>\n

Quel est l\u2019indice de transport (IT) pour un petit colis (moins de 1 m2<\/sup> de surface transversale) exp\u00e9di\u00e9 comme une \u00ab\u00a0cat\u00e9gorie\u00a0III \u2013 jaune\u00a0\u00bb avec les d\u00e9bits de dose suivants?<\/p>\n

Surface = 510\u00a0\u00b5Sv\/h
\n1 m\u00e8tre de la surface = 43\u00a0\u00b5Sv\/h
\n10 m\u00e8tres de la surface = 0,5\u00a0\u00b5Sv\/h<\/p>\n

R\u00e9ponses possibles\u00a0:
\na. 0,5
\nb. 4,3
\nc. 5,0
\nd. 8,6<\/p>\n

Solution propos\u00e9e\u00a0:<\/strong><\/p>\n

Pour les personnes qui envoient r\u00e9guli\u00e8rement des colis de classe\u00a07 ou qui ont assist\u00e9 \u00e0 la formation sur le TMD classe 7, cette question est un cadeau dans l\u2019examen pour l\u2019agr\u00e9ment (A)ACRP! Cependant, si vous n\u2019envoyez pas de substances nucl\u00e9aires ou n\u2019avez jamais entendu parler d\u2019\u00ab\u00a0indice de transport\u00a0\u00bb auparavant, cette question est un peu plus difficile.<\/p>\n

Si vous pr\u00e9voyez passer l\u2019examen pour l\u2019agr\u00e9ment (A)ACRP et que vous n\u2019envoyez pas de substances nucl\u00e9aires de fa\u00e7on r\u00e9guli\u00e8re, vous aurez \u00e0 \u00e9tudier le R\u00e8glement sur le transport des marchandises dangereuses (RTMD)<\/a> et le R\u00e8glement sur l\u2019emballage et le transport des substances nucl\u00e9aires (RETSN)<\/a>. Le RETSN est fourni lors de l\u2019examen, mais le RTMD et le R\u00e8glement de transport de mati\u00e8res radioactives (SSR-6) de l\u2019Agence internationale de l\u2019\u00e9nergie atomique (AIEA)<\/a> (en anglais) ne sont pas fournis. Le RETSN fait grandement r\u00e9f\u00e9rence aux deux autres r\u00e8glements, entre autres.<\/p>\n

L\u2019extrait suivant est tir\u00e9 de la section D\u00e9finitions du RETSN\u00a0:<\/p>\n

indice de transport<\/strong><\/em> S\u2019entend au sens du R\u00e8glement de l\u2019AIEA.<\/p>\n

\u00c9tant donn\u00e9 que vous ne disposerez pas du R\u00e8glement de l\u2019AIEA lors de l\u2019examen, vous devez l\u2019\u00e9tudier \u00e0 l\u2019avance. Avant de passer mon examen pour l\u2019agr\u00e9ment (A)ACRP, j\u2019avais suivi un cours de mise \u00e0 niveau pour la classe\u00a07 du RTMD. J\u2019ai fait d\u2019une pierre deux coups\u00a0: non seulement ai-je \u00e9tudi\u00e9 un peu mais j\u2019ai aussi obtenu une formation appropri\u00e9e au travail en m\u00eame temps!<\/p>\n

En \u00e9tudiant, vous d\u00e9couvrirez que conform\u00e9ment au r\u00e8glement de l\u2019AIEA<\/a> (pages\u00a062-63), l\u2019IT d\u2019un petit paquet est d\u00e9termin\u00e9 par la proc\u00e9dure suivante\u00a0:<\/p>\n

523 (a) D\u00e9terminez le niveau de rayonnement<\/em> maximal en millisieverts par heure (mSv\/h) \u00e0 une distance de 1\u00a0m des surfaces ext\u00e9rieures du colis, du suremballage, du conteneur ou des colis FAS-I et OSC-I non emball\u00e9s. La valeur d\u00e9termin\u00e9e doit \u00eatre multipli\u00e9e par 100 et le nombre obtenu est l\u2019IT.<\/p>\n

[\u2026]\n

(c) La valeur obtenue [\u2026] doit \u00eatre arrondie \u00e0 la premi\u00e8re d\u00e9cimale sup\u00e9rieure (par exemple, 1,13 devient 1,2), \u00e0 l\u2019exception des valeurs de 0,05 et moins qui sont consid\u00e9r\u00e9es comme z\u00e9ro.<\/p>\n

Pour la question de la rubrique, trois d\u00e9bits de dose \u00e9taient donn\u00e9s. Nous n\u2019avons vraiment besoin que du d\u00e9bit de dose \u00e0 1\u00a0m qui est de 43\u00a0\u00b5Sv\/h (les deux autres d\u00e9bits de dose n\u2019ont aucune incidence sur l\u2019indice de transport). Il s\u2019agit ensuite de convertir en mSv\/h.<\/p>\n

1\u2009000\u00a0\u00b5Sv\/h = 1\u00a0mSv\/h<\/p>\n

Ainsi\u00a0: 43\u00a0\u00b5Sv\/h = 0,043\u00a0mSv\/h<\/p>\n

Ensuite, selon le r\u00e8glement de l\u2019AIEA, il faut multiplier ce chiffre par 100. L\u2019IT n\u2019a pas d\u2019unit\u00e9, mais est de m\u00eame valeur que le d\u00e9bit de dose \u00e0 1\u00a0m en mrem\/h.<\/p>\n

0,043\u00a0mSv\/h \u00d7 100 = 4,3<\/p>\n

L\u2019IT est de 4,3 et la r\u00e9ponse \u00e0 la question est B.<\/p>\n

Nouvelle question\u00a0:<\/h1>\n

La quantit\u00e9 de lumi\u00e8re \u00e9mise par un luminophore \u00e0 scintillation est proportionnelle \u00e0 quelle caract\u00e9ristique de l\u2019\u00e9nergie photonique?<\/p>\n

a. Absorb\u00e9e
\nb. Att\u00e9nu\u00e9e
\nc. Diffus\u00e9e
\nd. Transmise<\/p>\n<\/div><\/div><\/div>

<\/div>\n
\n

\"\"Christopher Malcolmson<\/h2>\n

Christopher Malcolmson has been a health physicist at McMaster University since 2005.\u00a0He received a BSc from McMaster in 2004 and an MSc in 2011. He completed his CRPA(R) in 2009, American Board of Health Physics certification in 2012, and National Registry of Radiation Protection Technologists exam in 2016.\u00a0Malcolmson is currently a member of the CRPA board of directors (director of professional development) and the Registration Subcommittee exam coordinator. He is also a member of the International Radiation Protection Association\u2019s Commission on Publications.<\/p>\n

Christopher Malcolmson est sp\u00e9cialiste en radioprotection \u00e0 l\u2019Universit\u00e9 McMaster depuis 2005. Il a obtenu un baccalaur\u00e9at en sciences de cette m\u00eame universit\u00e9 en 2004, suivi d\u2019une ma\u00eetrise en 2011. Il a obtenu sa certification (A)ACRP en 2009, celle de l\u2019American Board of Health Physics (conseil am\u00e9ricain des sp\u00e9cialistes en radioprotection) en 2012, et a termin\u00e9 l\u2019examen de la National Registry of Radiation Protection Technologists (Registre national des technologues en radioprotection) en 2016. Malcolmson est pr\u00e9sentement membre du conseil d\u2019administration de l\u2019ACRP (directeur du perfectionnement professionnel) et coordonnateur de l\u2019examen au sous-comit\u00e9 des inscriptions. Il est \u00e9galement membre de la commission des publications de l\u2019Association internationale pour la protection contre les radiations.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

In this section of the Bulletin<\/em>, we introduce a question or two similar to the questions on the CRPA(R)\u00a0exam. \/ Dans cette section du Bulletin<\/em>, nous proposons une ou deux questions similaires \u00e0 celles qui se trouvent dans un examen pour l\u2019agr\u00e9ment (A)ACRP.<\/p>\n","protected":false},"author":31,"featured_media":995,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"footnotes":""},"categories":[5,4],"tags":[],"class_list":["post-1391","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-chroniques-regulieres","category-regular-columns"],"yoast_head":"\nCRPA(R) Prep, February 2019 \/ Pr\u00e9paration \u00e0 la d\u00e9signation (A)ACRP, f\u00e9vrier 2019 - CRPA-ACRP Bulletin<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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