{"id":7028,"date":"2025-09-17T11:58:10","date_gmt":"2025-09-17T17:58:10","guid":{"rendered":"https:\/\/www.crpa-acrp-bulletin.ca\/?p=7028"},"modified":"2025-09-17T11:58:10","modified_gmt":"2025-09-17T17:58:10","slug":"coin-du-specialiste-de-la-radioprotection-septembre-2025","status":"publish","type":"post","link":"https:\/\/www.crpa-acrp-bulletin.ca\/fr\/2025\/09\/17\/coin-du-specialiste-de-la-radioprotection-septembre-2025\/","title":{"rendered":"Coin du sp\u00e9cialiste de la radioprotection, septembre 2025"},"content":{"rendered":"<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5656 size-full alignnone\" src=\"https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Coin-du-specialiste-de-la-radioprotection-FR-header.png\" alt=\"\" width=\"539\" height=\"171\" srcset=\"https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Coin-du-specialiste-de-la-radioprotection-FR-header.png 539w, https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Coin-du-specialiste-de-la-radioprotection-FR-header-300x95.png 300w, https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Coin-du-specialiste-de-la-radioprotection-FR-header-520x165.png 520w, https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Coin-du-specialiste-de-la-radioprotection-FR-header-320x102.png 320w\" sizes=\"auto, (max-width: 539px) 100vw, 539px\" \/><\/p>\n<h1 style=\"font-weight: 400;\">D\u00e9fi reli\u00e9 au cyclotron : Combien de fluor 18 peut \u00eatre g\u00e9n\u00e9r\u00e9\u2009?<\/h1>\n<div>\n<p><span lang=\"FR-CA\">Bienvenue \u00e0 nouveau au Coin du sp\u00e9cialiste de la radioprotection\u2009!<\/span><\/p>\n<\/div>\n<p style=\"font-weight: 400;\">Dans ce num\u00e9ro, nous nous int\u00e9ressons \u00e0 l\u2019activit\u00e9 du fluor 18. Un cyclotron destin\u00e9 \u00e0 la production d\u2019isotopes pour la tomographie par \u00e9mission de positons (TEP) poss\u00e8de une \u00e9nergie de faisceau de protons de 19 MeV et un courant maximal sur la cible de 200 \u00b5A. Le taux de production nominal de l\u2019activit\u00e9 du fluor 18 g\u00e9n\u00e9r\u00e9e dans une cible d\u2019eau enrichie en oxyg\u00e8ne 18 par le biais de l\u2019interaction\u00a0<sup>18<\/sup>O \u2192 (p,n) \u2192 <sup>18<\/sup>F \u00e0 l\u2019aide de protons de 19\u00a0MeV est d\u2019environ 14\u00a0GBq \u00b5A<sup>-1<\/sup>.<\/p>\n<h2>Question 1<\/h2>\n<p>A) Quelle est l\u2019activit\u00e9 maximale possible de fluor 18 pouvant \u00eatre g\u00e9n\u00e9r\u00e9e pendant une irradiation de 3 heures\u2009?<\/p>\n<p style=\"font-weight: 400;\"><strong>        <div class=\"rmwr-wrapper\"\r\n             data-id=\"rmwr-p7028-1\"\r\n                          data-key=\"p7028-1\"\r\n                          data-post=\"7028\"\r\n                          data-animation=\"none\"\r\n                          data-duration=\"300\"\r\n                          data-mode=\"normal\"\r\n                          data-lazy=\"false\"\r\n                          data-smooth-scroll=\"true\"\r\n                          data-scroll-offset=\"0\"\r\n             >\r\n            <button\r\n                type=\"button\"\r\n                class=\"read-link \"\r\n                id=\"readlinkrmwr-p7028-1\"\r\n                data-open-text=\"Show Answer\"\r\n                data-close-text=\"Hide Answer\"\r\n                                aria-expanded=\"false\"\r\n                aria-controls=\"readrmwr-p7028-1\"\r\n            >\r\n                                <span class=\"rmwr-text\">Show Answer<\/span>\r\n            <\/button>\r\n            <div\r\n                class=\"read_div\"\r\n                id=\"readrmwr-p7028-1\"\r\n                aria-hidden=\"true\"\r\n                style=\"display: none;\"\r\n            >\r\n                                    <\/strong><\/p>\n<h2 style=\"font-weight: 400\"><strong>Answer 1<\/strong><\/h2>\n<p style=\"font-weight: 400\">Durant l\u2019irradiation, la d\u00e9sint\u00e9gration rivalise avec la production<\/p>\n<p style=\"font-weight: 400\">\u00a0\u00a0 R = N\u03bb(1 \u2013 e<sup>\u2013\u03bbt<\/sup>)<\/p>\n<p style=\"font-weight: 400\">R est le taux de production des noyaux radioactifs (GBq \u00b5A<sup>-1<\/sup>). Le terme (1 \u2013 e<sup>\u2013\u03bbt<\/sup>) est appel\u00e9 le \u00ab\u00a0facteur de saturation\u00a0\u00bb et tient compte de la d\u00e9sint\u00e9gration pendant la p\u00e9riode d\u2019irradiation <em>t<\/em> de la cible.<\/p>\n<p style=\"font-weight: 400\">La saturation se produit lorsque <em>t<\/em> &gt;&gt; T\u00bd, de sorte que e<sup>\u2013\u03bbt<\/sup> \u2248 0, le facteur de saturation est de 1 et R = N\u03bb (c\u2019est-\u00e0-dire que le taux de d\u00e9sint\u00e9gration est \u00e9gal au taux de production).<\/p>\n<p style=\"font-weight: 400\">T\u00bd pour <sup>18<\/sup>F est de 1,83\u00a0heure, ainsi \u03bb = 0,693\/1,83 = 0,38\u00a0h<sup>-1<\/sup><\/p>\n<p style=\"font-weight: 400\">Le facteur de saturation est 1 &#8211; e<sup>-0,38 \u00d7 3<\/sup> = 0,68<\/p>\n<p style=\"font-weight: 400\"><span style=\"font-weight: 400\">200\u00a0\u00b5A \u00d7 14\u00a0GBq \u00b5A<sup>-1<\/sup> \u00d7 0,68 = 1\u2009904\u00a0GBq<\/span><\/p>\n                            <\/div>\r\n                    <\/div>\r\n        \n<h2>Question 2<\/h2>\n<p>B) Quel serait le d\u00e9bit de dose efficace non blind\u00e9 approximatif \u00e0 3 m\u00e8tres de la cible pendant l\u2019irradiation\u2009?<\/p>\n<p style=\"font-weight: 400;\"><strong>        <div class=\"rmwr-wrapper\"\r\n             data-id=\"rmwr-p7028-2\"\r\n                          data-key=\"p7028-2\"\r\n                          data-post=\"7028\"\r\n                          data-animation=\"none\"\r\n                          data-duration=\"300\"\r\n                          data-mode=\"normal\"\r\n                          data-lazy=\"false\"\r\n                          data-smooth-scroll=\"true\"\r\n                          data-scroll-offset=\"0\"\r\n             >\r\n            <button\r\n                type=\"button\"\r\n                class=\"read-link \"\r\n                id=\"readlinkrmwr-p7028-2\"\r\n                data-open-text=\"Show Answer\"\r\n                data-close-text=\"Hide Answer\"\r\n                                aria-expanded=\"false\"\r\n                aria-controls=\"readrmwr-p7028-2\"\r\n            >\r\n                                <span class=\"rmwr-text\">Show Answer<\/span>\r\n            <\/button>\r\n            <div\r\n                class=\"read_div\"\r\n                id=\"readrmwr-p7028-2\"\r\n                aria-hidden=\"true\"\r\n                style=\"display: none;\"\r\n            >\r\n                                    <\/strong><\/p>\n<h2 style=\"font-weight: 400\"><strong>Answer 2<\/strong><\/h2>\n<p style=\"font-weight: 400\">R est \u00e9galement le taux auquel les neutrons sont produits\u2009!<\/p>\n<p style=\"font-weight: 400\">Un n pour chaque r\u00e9action (p,n), donc le taux de production est de 200\u00a0\u00b5A \u00d7 14\u00a0GBq \u00b5A<sup>-1<\/sup> = 2,8 \u00d7 10<sup>12<\/sup>\u00a0n sec<sup>-1<\/sup><\/p>\n<p style=\"font-weight: 400\">En supposant une distribution isotrope, \u00e0 3\u00a0m\u00e8tres de la cible, le taux de fluence est de<\/p>\n<ul>\n<li>\u0424<sub>n<\/sub> =2,8 \u00d7 10<sup>12<\/sup>n sec<sup>-1<\/sup> \/ 4\u00a0\u03c0 (300\u00a0cm)<sup>2<\/sup><\/li>\n<li>\u0424<sub>n<\/sub> = 2,48 \u00d7 10<sup>6<\/sup>n sec<sup>-1<\/sup> cm<sup>2<\/sup><\/li>\n<\/ul>\n<p style=\"font-weight: 400\">L\u2019\u00e9nergie des neutrons peut atteindre plusieurs MeV et le facteur de conversion de la fluence en dose varie consid\u00e9rablement en fonction de l\u2019\u00e9nergie et de l\u2019orientation de l\u2019exposition. Dans le pire des cas, le facteur de conversion (diverses r\u00e9f\u00e9rences de la CIPR) serait d\u2019environ 400\u00a0pSv n<sup>-1<\/sup> cm<sup>-2<\/sup>.<\/p>\n<ul>\n<li>2,48 \u00d7 10<sup>6<\/sup>n sec<sup>-1 <\/sup>cm<sup>2<\/sup> x (4 x 10<sup>-10<\/sup> Sv n<sup>-1<\/sup> cm<sup>-2<\/sup>)<\/li>\n<li>0,99 mSv s<sup>-1<\/sup> or 3,6\u00a0Sv h<sup>-1<\/sup><\/li>\n<\/ul>\n                            <\/div>\r\n                    <\/div>\r\n        \n<h2>R\u00e9f\u00e9rences recommand\u00e9es<\/h2>\n<ul>\n<li><em>IAEA TRS465 Cyclotron Produced Radionuclides: Principles and Practice<\/em> (en anglais seulement)<\/li>\n<li><em>IAEA TRS468 Cyclotron Produced Radionuclides: Physical Characteristics and Production Methods <\/em>(en anglais seulement)<\/li>\n<\/ul>\n<p>&nbsp;<\/p>\n<div style=\"padding: 10px 10px 0 10px; background-color: #eeeeee; border: #dddddd 2px solid;\">\n<h2><img loading=\"lazy\" decoding=\"async\" class=\"alignright wp-image-5647 size-thumbnail\" src=\"https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Jeff-Sandeman-bio-pic-cropped-150x150.png\" alt=\"\" width=\"150\" height=\"150\" srcset=\"https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Jeff-Sandeman-bio-pic-cropped-150x150.png 150w, https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Jeff-Sandeman-bio-pic-cropped-80x80.png 80w, https:\/\/www.crpa-acrp-bulletin.ca\/wp-content\/uploads\/2024\/01\/Jeff-Sandeman-bio-pic-cropped-244x245.png 244w\" sizes=\"auto, (max-width: 150px) 100vw, 150px\" \/>Jeff Sandeman<\/h2>\n<p>Jeff\u00a0se d\u00e9crit comme un \u00ab\u00a0vieux rousp\u00e9teur grognon\u00a0\u00bb qui a pris sa retraite de la division des acc\u00e9l\u00e9rateurs et des installations de classe\u00a0II de la CCSN en janvier\u00a02021 apr\u00e8s 17\u00a0ans au sein de la division. Avant \u00e7a, il a pass\u00e9 20\u00a0ans chez ActionCancer Manitoba. Durant ses derni\u00e8res ann\u00e9es \u00e0 cet endroit, il a \u00e9t\u00e9 responsable de la radioprotection pour les installations de radioth\u00e9rapie.<\/p>\n<p>Tout au long de ses deux carri\u00e8res, il a eu de nombreuses occasions d\u2019explorer une vaste gamme de sujets li\u00e9s \u00e0 la radioprotection, y compris les rayons\u00a0X non ionisants, de diagnostic, la m\u00e9decine nucl\u00e9aire, la radioth\u00e9rapie m\u00e9dicale, la production d\u2019isotopes par cyclotron et m\u00eame les acc\u00e9l\u00e9rateurs de recherche \u00e0 haute \u00e9nergie. Pour une raison \u00e9trange, les deux \u00e9tablissements lui ont aussi permis d\u2019enseigner les fondements de la radioprotection et la conception de protection contre les rayonnements et d\u2019offrir du mentorat (corrompre) les jeunes membres du personnel. Le point culminant de sa vie professionnelle a \u00e9t\u00e9 en 2020 quand l\u2019ACRP lui a remis le <a href=\"https:\/\/www.crpa-acrp-bulletin.ca\/fr\/2020\/07\/08\/laureats-2020-de-lacrp\/\">Prix de fondateur comm\u00e9moratif Richard V.\u00a0Osborne<\/a>.<\/p>\n<p><span style=\"font-weight: 400;\">Maintenant que Jeff est \u00e0 la retraite, il passe la majorit\u00e9 de son temps \u00e0 essayer de golfer (avec peine), faire de la poussi\u00e8re dans le sous-sol (menuiserie) ou \u00e0 collectionner des morceaux de papier souill\u00e9 (c.-\u00e0-d. des timbres). Il adore le whisky \u00e9cossais single malt et en a d\u2019ailleurs plus de bouteilles que ce que son foie peut prendre. Il continue de toucher \u00e0 la radioprotection et est toujours membre de l\u2019ACRP (habituellement apr\u00e8s 18\u00a0rappels de renouveler son adh\u00e9sion puisqu\u2019il perd la m\u00e9moire en raison de son \u00e2ge).<\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div style=\"padding: 10px 10px 10px 10px; background-color: #eeeeee; border: #dddddd 2px solid;\">\n<h2 style=\"color: #e93b25;\">Vous voulez lire d\u2019autres articles comme celui-ci ?<\/h2>\n<p>Le\u00a0<em>Bulletin<\/em> de l\u2019Association canadienne de la radioprotection (ACRP) est une publication essentielle \u00e0 tout professionnel de la radioprotection du Canada. Son contenu \u00e9ditorial procure aux professionnels de la radioprotection les enseignements, l\u2019information, les conseils et les solutions utiles, tous n\u00e9cessaires pour demeurer \u00e0 l\u2019avant-garde de la profession.<\/p>\n<p>Abonnez-vous aujourd\u2019hui pour que nous vous envoyions un courriel chaque fois qu\u2019un nouveau num\u00e9ro est mis en ligne. Revisitez souvent le site entre chaque num\u00e9ro pour obtenir les mises \u00e0 jour et consulter de nouveaux articles.<\/p>\n<p>Ne ratez aucun num\u00e9ro. Abonnez-vous d\u00e8s aujourd\u2019hui !<\/p>\n<a class=\"maxbutton-3 maxbutton maxbutton-abonnez-vous\" target=\"_blank\" title=\"Abonnez-vous !\" rel=\"noopener\" href=\"https:\/\/mailchi.mp\/3cpublications\/5baszj3vti\"><span class='mb-text'>Abonnez-vous<\/span><\/a>\n<\/div>\n<p style=\"font-weight: 400;\">\n","protected":false},"excerpt":{"rendered":"<p>Ce Coin du sp\u00e9cialiste de la radioprotection porte sur la production de fluor 18 dans un cyclotron pour TEP. Quelle activit\u00e9 de fluor 18 peut \u00eatre g\u00e9n\u00e9r\u00e9e pendant une irradiation de 3 heures? Quel est le d\u00e9bit de dose efficace non blind\u00e9 approximatif \u00e0 3 m\u00e8tres?<\/p>\n","protected":false},"author":128,"featured_media":6637,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"footnotes":""},"categories":[28],"tags":[],"class_list":["post-7028","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-chroniques-regulieres-fr"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v28.2 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Coin du sp\u00e9cialiste de la radioprotection, septembre 2025 - CRPA-ACRP Bulletin<\/title>\n<meta name=\"description\" content=\"Ce Coin du sp\u00e9cialiste de la radioprotection porte sur la production de fluor 18 dans un cyclotron pour TEP : l\u2019activit\u00e9 g\u00e9n\u00e9r\u00e9e pendant une irradiation de 3 heures et le d\u00e9bit de dose \u00e0 3 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